困難反騎士數獨

相距騎士步的儲存格不能有相同數字。這是一個影響每一行每一列的全局約束。

困難 反騎士數獨。稀疏的給定數字和長的跨單元騎士鏈使這成為一個要求高的解題——在開始推理之前初始化所有騎士刪除。

1
2
9
8
4
6
5
1
2
9
9
2
3
7
4
2
7
8
3
5
7
6
9
5
5
3
6
錯誤
0/3
分數
-
時間
00:00
嘗試專家反騎士數獨 →
進度0%
♞ 騎士移動限制啟用

什麼是 反騎士數獨?

難度
★★★☆☆
3/5
約束類型
反限制
典型給定數
20–26
平均解題時間(困難)
24分鐘

解題技巧:困難 等級

技巧 描述 等級
Knight-Zone Mapping For each cell, mark all potential knight-move destinations (up to 8 cells). None may share the same digit as the source cell. 初學者
Corner and Edge Advantage Corner cells have only 2 knight-move neighbours; edge cells have at most 4. These restricted zones are easiest to resolve first. 初學者
Knight Chains Placing a digit can eliminate it from a chain of knight-move positions that span diagonally across the grid. 中級
Graph Coloring Model the knight-move network as a graph and two-color it to find cells that cannot share a digit. 進階

準備好終極測試了嗎?試試 專家 反騎士數獨 — 數獨 上最難的謎題。

在 困難 需要掌握的技巧

  • Hidden Pairs technique — Hard Anti-Knight grids hide pairs in cells whose other candidates were removed by L-shaped eliminations two moves earlier — keep notes scrupulously current to see them.
  • X-Wing 技巧 — The knight constraint often leaves a digit exactly two legal cells per row across distant boxes — prime X-Wing geometry that classic grids take far longer to produce.

依難度平均解題時間

簡單
5分鐘
中等
12分鐘
困難
24分鐘
專家
45分鐘
想要規則、策略和解題步驟的完整演練嗎? 如何遊玩 反騎士數獨 →

相關變體

反國王數獨

The shorter-range chess rule — repeats forbidden among all eight touching cells rather than across L-shaped leaps.

反連續數獨

Trades geometric reach for value logic: orthogonal neighbours may never hold consecutive digits.

非連續數獨

Same constraint family — a global unmarked rule whose eliminations cascade after every placement.

常見問題 — 困難 反騎士數獨

困難的反騎士數獨為何困難?
困難的反騎士謎題有稀疏的給定數字,需要跨越數個單元的長騎士移動鏈。你必須同時追蹤行、列、宮和騎士移動約束,同時維護完整的候選數網格——忽略任何一個通常會導致死胡同。
如何在hard Anti-Knight Sudoku中找到突破?
尋找一個在整行或整列中僅限於兩個儲存格的數字。然後檢查每個候選儲存格的騎士移動鄰居——如果其中一個鄰居已經包含該數字,則該候選數被排除,只剩下一個選項,從而突破謎題。
什麼是 knight's-move X-Wing 模式?
A knight's-move X-Wing occurs when a digit has exactly two candidate cells in each of two rows, and those cells are knight's-move distances apart in a symmetric pattern. This allows eliminations in multiple columns simultaneously, combining standard X-Wing logic with the knight's constraint.
在hard Anti-Knight Sudoku中,full candidate initialization有多重要?
關鍵。在進行任何推導之前,從每個給定數字應用騎士約束。每個給定數字會產生遠超其自身行、列和宮的排除。困難謎題依賴這些延伸排除才能可解,早期錯過它們會使謎題看起來比實際困難得多。
一個hard Anti-Knight Sudoku需要多長時間來解題?
預計30–55分鐘用於困難謎題。從一開始就完成完整騎士移動初始化的玩家通常可以節省10–15分鐘的解題時間。

還有問題?請參閱完整 反騎士數獨指南.